8c^2+26c=24

Solution for 8c^2+26c=24 equation:

8c^2+26c=24

We move all terms to the left:

8c^2+26c-(24)=0

a = 8; b = 26; c = -24;
Δ = b2-4ac
Δ = 262-4·8·(-24)
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-38}{2*8}=\frac{-64}{16}
=-4
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+38}{2*8}=\frac{12}{16}
=3/4
$